Solved Problems
Q 1) Calculate the equivalent resistance across AB. Find the
current draw from the battery. You may refer figure 5.1.
a)
Then find the voltage across 9 Ohms resistance.
b)
Find the voltage between AD.
c)
Find the current through 18 Ohms resistance.
Answer :
Resistance across AC = (6/2) = 3 Ohms-----------( as the
resistance are equal, R = r/n )
Resistance across AD = (3+6) // 18 = {9*18/ (9+18)} = 6 Ohms
Resistance across AB = 6+9 = 15 Ohms
Now we can find the current drag from the battery by using
this equivalent resistance across AB.
Ohm’s law to Rab,
V = IR
60V = I X 15
I = 4A
a) As
there are no parallel paths between AB , current through 9 Ohms resistance is
equal to 4A . Ohm’s law to 9 Ohms resistor,
V = IR
Vdb = 4A x 9 Ohms
Vdb = 36V
V = IR
Vdb = 4A x 9 Ohms
Vdb = 36V
b) Since,
V ab = V ad + V db
V ad = Vab – V db
V ad = 60 – 36
V ad = 24 V
V ab = V ad + V db
V ad = Vab – V db
V ad = 60 – 36
V ad = 24 V
c) Current
through 18 Ohms can be calculate by Ohm’s
law
Vad = I x 18
I = (24/18) A
I = (4/3) A
Vad = I x 18
I = (24/18) A
I = (4/3) A
Q2) Find the
equivalent resistance across AB in every circuit.
i)
Each resistance is 3 Ohms
Figure 5.2
Answer :
Figure 5.2.1
Figure 5.2.1 shows the way to calculate the equivalent
resistant
Rab
=
3 + 1.5 + 1 + 3 = 8.5 Ohms
ii)
Answer :
Then we can simplify this circuit as shown in figure 5.3.2
After therse steps the problem becomes a very simple one.
Rab
= 0.5 Ohms
Exercise
Q3)
i)
Find the current draw from the circuit in
figure 5.2 (Q2. i ) if 60 V voltage is given to AB .
ii)
Find the voltage difference between
every resistance
iii)
Then find the current through every
resistance
Q4)i) Find the current draw from the circuit in figure 5.3 (Q2. ii ) if 60 V voltage is given to AB .
ii) Find the voltage difference between every resistance
iii) Then find the current through every resistance
Q5) i) Find the total current draw from the battery in Figure 6.1 Ans (3A)
ii) Calculate the power supplied by battery in figure 6.2 Ans(72W)
iii) Find the total resistance seen by the battery in figure 6.3 . find the current draw from it.
Ans (1.5 Ohms , 8A )
NOTE : In figure 6.1 The resistance are parallel connected (12 Ohms & 6 Ohms ) .
In figure 6.2 Again you may see that all three resistors are parallel connected.
In figure 6.3 Again you may see that all four resistors are parallel connected.
to understand these things you need to solve more problems and gain experience.
B.sc (Engineering undergraduate)
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