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**Star, Delta circuits**

__Delta/Star transformation__
When solving networks with considerable number of branches,
sometimes we experiences a great difficulty due to a large number of unknown
variable have to be find. Such complicated networks can be simplified by successively
replacing delta meshes by equivalent star systems and vice versa.

Consider we have three resistances connected in delta
fashion between terminals 1, 2 and 3 as shown in figure 15.1(a). These three
resistances can be replaced by three star connected (or ‘Y’ connected)
resistances as shown in figure 15.1(b).

If we can arrange these three resistances in such a way that
both delta and star systems will show the same resistance between any pair of
terminals we can replace any of these arrangement instead of the other
one. This means these two arrangements
are electrically equivalent.

**How to convert a delta connection to star connection?**

In the delta connection, there are two parallel paths
between terminals 1 & 2. One is having a resistance of R

_{12}and the other is having a resistance of (R_{23}+R_{31}).
So the resistance between terminals 1&2 = R

_{12}// (R_{23}+R_{31})
In the star connection, the resistance between the same
terminals = R

_{1}+ R_{2}
For electrically equivalent arrangements these two values
should be equal, so

**R**

_{1}+ R_{2 }= R_{12}X (R_{23}+R_{31}) / (R_{12}+R_{23}+R_{31}) --------------------- (A)
Similarly for terminals 2 & 3 and terminal 3 & 1, we
get

**R**

_{2}+ R_{3}= R_{23}X (R_{31}+R_{12}) / (R_{12}+R_{23}+R_{31}) --------------------- (B)**R**

_{3}+ R_{1}= R_{31}X (R_{12}+R_{23}) / (R_{12}+R_{23}+R_{31}) ---------------------(C)
By solving these three equations,

*R*_{1}= R_{12}R_{31}/ (R_{12}+R_{23}+R_{31})

*R*_{2}= R_{23}R_{12}/ (R_{12}+R_{23}+R_{31})

*R*_{3}= R_{31}R_{23}/ (R_{12}+R_{23}+R_{31})

__Star/Delta transformation__
This can be easily done by using equations (A), (B) and (C)

1.
Multiply A&B , B&C and A&C

2.
Add them together and simplify them.

Then we get,

*R*_{12}= R_{1}+ R_{2}+ (R_{1}R_{2}/R_{3})

*R*_{23}= R_{2}+ R_{3}+ (R_{2}R_{3}/R_{1})

*R*_{31}= R_{3}+ R1 + (R_{3}R_{1}/R_{2})***You do not need to hardly remember these equations. You must be intelligent enough to understand the pattern of these equations. We will discuss some solved problems in my next post.**

My next post will be a “solved problems” post regarding
everything we’ve learnt so far in network analysis

Pabindu lakshitha

B.Sc (Engineering Undergraduate)

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