tag:blogger.com,1999:blog-2712495251493650893.post1283224548247949161..comments2023-09-19T08:56:47.339-07:00Comments on Fundamentals of Electrical Engineering: SOLVED PROBLEMS ON THEVENIN'S THEOREM (1)pabinduhttp://www.blogger.com/profile/01651170864878300196noreply@blogger.comBlogger49125tag:blogger.com,1999:blog-2712495251493650893.post-33210861965594052732019-11-09T04:54:23.766-08:002019-11-09T04:54:23.766-08:00wrong but the vth value is 11.25
wrong but the vth value is 11.25<br />Nithinhttps://www.blogger.com/profile/13758318386235274310noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-18417969412466242642019-11-09T04:48:16.352-08:002019-11-09T04:48:16.352-08:00yes
yes<br />Nithinhttps://www.blogger.com/profile/13758318386235274310noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-55963114570899967542019-11-09T04:41:52.472-08:002019-11-09T04:41:52.472-08:00for do that problem just do like this
10/10+5*32
...for do that problem just do like this <br />10/10+5*32<br />then we will get vth valueNithinhttps://www.blogger.com/profile/13758318386235274310noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-36676009874189322432019-09-09T08:47:06.482-07:002019-09-09T08:47:06.482-07:00Thanks for good examples
These helped me to un...Thanks for good examples <br /> These helped me to understand betterAnonymoushttps://www.blogger.com/profile/06303563818586401000noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-46399210802839130742018-09-10T03:55:15.657-07:002018-09-10T03:55:15.657-07:00Why you minus by on the Vd nodal analysis
Why you minus by on the Vd nodal analysis<br />Anonymoushttps://www.blogger.com/profile/05271318876307197927noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-69349683416626344862018-09-04T10:16:48.010-07:002018-09-04T10:16:48.010-07:00how can we actually know where to use nodal analys...how can we actually know where to use nodal analysis method?<br />we can also use the Kirchoff's laws to find Vth Rth right. So basically where exactly we can use nodal analysis method?Anonymoushttps://www.blogger.com/profile/01540057392143570476noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-49307411113286194862017-10-17T04:38:17.799-07:002017-10-17T04:38:17.799-07:00Thank you for selecting the best forum to say it Thank you for selecting the best forum to say it pabinduhttps://www.blogger.com/profile/01651170864878300196noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-82413386906406343532017-10-17T04:37:23.596-07:002017-10-17T04:37:23.596-07:00Hellow Hans Lim,
It seems you must study nodal eq...Hellow Hans Lim, <br />It seems you must study nodal equation method. Please follow below link which will lead you to my post on nodal equation method. <br />Take 30 mins and study this post. It will solve all your problems. <br />https://eefundamentals.blogspot.com/2012/08/network-analysis-3.html<br /><br />Thank you. <br />Pabindu Gamage. <br />B.Sc Eng (Hons)pabinduhttps://www.blogger.com/profile/01651170864878300196noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-86093114749480361512017-10-17T04:35:59.272-07:002017-10-17T04:35:59.272-07:00Hellow Hans Lim,
It seems you must study nodal eq...Hellow Hans Lim, <br />It seems you must study nodal equation method. Please follow below link which will lead you to my post on nodal equation method. <br />Take 30 mins and study this post. It will solve all your problems. <br />https://eefundamentals.blogspot.com/2012/08/network-analysis-3.html<br /><br />Thank you. <br />Pabindu Gamage. <br />B.Sc Eng (Hons)pabinduhttps://www.blogger.com/profile/01651170864878300196noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-14829937095134889772017-10-17T04:33:53.765-07:002017-10-17T04:33:53.765-07:00This comment has been removed by the author.pabinduhttps://www.blogger.com/profile/01651170864878300196noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-78203879961052714872017-10-16T11:38:20.016-07:002017-10-16T11:38:20.016-07:00send more problems with dependent sourcessend more problems with dependent sourcesterashttps://www.blogger.com/profile/13361005808455167577noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-6931561265653194182017-10-11T21:19:51.748-07:002017-10-11T21:19:51.748-07:00also from what i learned its higher potential to l...also from what i learned its higher potential to lower potential, (30-v)/5 :/ cauuse there would probably be a voltage drop. idk i wnna clear things upAnonymoushttps://www.blogger.com/profile/14869535403471352722noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-76073495192956155962017-10-11T21:09:35.861-07:002017-10-11T21:09:35.861-07:00(V-30)/5 + (V-0)/10 = 0
V = 20V [why is it (+),...(V-30)/5 + (V-0)/10 = 0<br /><br />V = 20V [why is it (+), so does that mean both current enters the node? and (v/10) is a current that's from the ground??]Anonymoushttps://www.blogger.com/profile/14869535403471352722noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-49881710838784433402017-10-11T20:48:50.200-07:002017-10-11T20:48:50.200-07:00This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/14869535403471352722noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-76928687334442046532017-10-08T00:45:00.759-07:002017-10-08T00:45:00.759-07:00Sir please solve the last sum in mesh analysis als...Sir please solve the last sum in mesh analysis alsoBloggy Treatshttps://www.blogger.com/profile/17009862916339544356noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-28264068332258357112017-10-08T00:43:46.295-07:002017-10-08T00:43:46.295-07:00Sir please solve the last sum in mesh analysis als...Sir please solve the last sum in mesh analysis alsoBloggy Treatshttps://www.blogger.com/profile/17009862916339544356noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-1412932511076294782017-06-27T20:49:05.547-07:002017-06-27T20:49:05.547-07:00This has really been helpful. Please, what if the ...This has really been helpful. Please, what if the circuit only has a current sourceAnonymoushttps://www.blogger.com/profile/04374680606974027517noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-83522201847383656742017-06-05T21:39:58.769-07:002017-06-05T21:39:58.769-07:00Why ideal current is subtracted in Q3? Why ideal current is subtracted in Q3? Dkumarhttps://www.blogger.com/profile/02365213536227048231noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-69786124915001195552017-06-05T21:39:17.333-07:002017-06-05T21:39:17.333-07:00Why ideal current is subtracted in Q3? Why ideal current is subtracted in Q3? Dkumarhttps://www.blogger.com/profile/02365213536227048231noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-1120567777000538202017-01-28T00:21:45.756-08:002017-01-28T00:21:45.756-08:00PAKISTAN is great
PAKISTAN is great<br />Anonymoushttps://www.blogger.com/profile/06211593372125658106noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-22295028281468874902016-12-13T06:30:18.095-08:002016-12-13T06:30:18.095-08:00Using Thevenin’s theorem, what is the load
current...Using Thevenin’s theorem, what is the load<br />current in Fig. 1-9a for the following values of RL: 2 kV, 6 kV, and 18 kV?<br />If you really want to appreciate the power of Thevenin’s theorem, try<br />calculating the foregoing currents using the original circuit of Fig. 1-9a and any<br />other method.<br /><br /><br />Rth=6kohm<br />24vSeemab Mirhttps://www.blogger.com/profile/09255479886041626243noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-83451444086975627232016-11-24T00:24:52.561-08:002016-11-24T00:24:52.561-08:00what if in question 3 I add a voltage source in se...what if in question 3 I add a voltage source in series with 5 ohm resistor which was neglected in calculating the Vth . Will the voltage source be neglected too and Vc=Va hold true?Anonymoushttps://www.blogger.com/profile/08611930661727644202noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-62066626728362875452016-11-21T23:24:41.193-08:002016-11-21T23:24:41.193-08:00Wish you are mentioning the 10 ohm resistor at poi...Wish you are mentioning the 10 ohm resistor at point D in parallel with the current source.<br />(VC – 0)/3 + (VC-5)/ 12 = 0<br /><br />Solve this an find Vc.<br />Then<br />(VD - VC)/2 + (VD -5)/10 – 1 = 0 <br />Find Vd. <br />You must re calculate Rth without 10 Ohms resistor. <br />pabinduhttps://www.blogger.com/profile/01651170864878300196noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-57653157807170782852016-11-12T02:32:26.307-08:002016-11-12T02:32:26.307-08:00if there is no 10 ohm resistor in figure 11.6 the...if there is no 10 ohm resistor in figure 11.6 then what are the two equation for solving Vth? can you please help me?Anonymoushttps://www.blogger.com/profile/12549414500548773057noreply@blogger.comtag:blogger.com,1999:blog-2712495251493650893.post-390001311155750852016-11-12T02:27:04.999-08:002016-11-12T02:27:04.999-08:00This comment has been removed by the author.Anonymoushttps://www.blogger.com/profile/12549414500548773057noreply@blogger.com